(3x+1)(x^4-16)=0

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Solution for (3x+1)(x^4-16)=0 equation: 


Simplifying
(3x + 1)(x4 + -16) = 0

Reorder the terms:
(1 + 3x)(x4 + -16) = 0

Reorder the terms:
(1 + 3x)(-16 + x4) = 0

Multiply (1 + 3x) * (-16 + x4)
(1(-16 + x4) + 3x * (-16 + x4)) = 0
((-16 * 1 + x4 * 1) + 3x * (-16 + x4)) = 0
((-16 + 1x4) + 3x * (-16 + x4)) = 0
(-16 + 1x4 + (-16 * 3x + x4 * 3x)) = 0
(-16 + 1x4 + (-48x + 3x5)) = 0

Reorder the terms:
(-16 + -48x + 1x4 + 3x5) = 0
(-16 + -48x + 1x4 + 3x5) = 0

Solving
-16 + -48x + 1x4 + 3x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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